Can you find this amazing question?
Proof:
Here is the “proof” in text.
2 = 1 + 1
2 = 1 + √(1)
2 = 1 + √(-1 * -1)
2 = 1 + √(-1)√(-1)
2 = 1 + i(i)
2 = 1 + i2
2 = 1 + (-1)
2 = 0
2 = 1 + √(1)
2 = 1 + √(-1 * -1)
2 = 1 + √(-1)√(-1)
2 = 1 + i(i)
2 = 1 + i2
2 = 1 + (-1)
2 = 0
This is not correct proof.
Or keep reading for a text explanation.
False Proof 2 = 0
2 = 1 + 1
2 = 1 + √(1)
2 = 1 + √(-1 * -1)
2 = 1 + √(-1)√(-1)
2 = 1 + i(i)
2 = 1 + i2
2 = 1 + (-1)
2 = 0
2 = 1 + √(1)
2 = 1 + √(-1 * -1)
2 = 1 + √(-1)√(-1)
2 = 1 + i(i)
2 = 1 + i2
2 = 1 + (-1)
2 = 0
The mistake is between lines 3 and 4.
√(-1 * -1) ≠ √(-1)√(-1)
This is a misapplication of the product rule for square roots. The product rule is guaranteed to work only when both values are positive.
If x, y ≥ 0, then
√(xy) = √(x)√(y)
√(xy) = √(x)√(y)
When x = y = -1, the product rule may not apply, and as demonstrated, it is not a valid step because it leads to the conclusion that 2 = 0.
Thank you for reading...
By:vikash rahii
Can you prove 0 = 2 ?
Reviewed by biharishayar
on
February 08, 2018
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